POJ刷题历程

简介

巨坑填不上QAQ

1003 Hangover

一句话题意:给一个浮点数limit,求$\sum_{i=2}^Ans{\frac{1}{i}} <= limit$的最大Ans值

一句话题解:暴力

代码:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
#include <cstdio>
#include <cstring>
#include <iostream>
int main() {
float res[300] = {0,0.5}, c;
int num = 0;
for (int i = 2; i < 300; ++i)
res[i] = res[i - 1] + 1.0/ (i + 1);
while (scanf("%f", &c) && c)
for (int i = 1; i < 300; ++i)
if (res[i] >= c) {
printf("%d card(s)\n",i);
break;
}
return 0;
}

文章目录
  1. 1. 简介
  2. 2. 1003 Hangover
,